Math 2.0

Ordinary differential equations Complex domain and special equations Example

Hermite equation

Example

Let λ∈ℂ\lambda \in \C. The Hermite equation is y′′−2z y′+2λ y=0.y'' - 2 z\, y' + 2 \lambda\, y = 0. Its coefficients −2z-2z and 2λ2 \lambda are polynomials, so every point of ℂ\C is an ordinary point. A power series solution y=∑k≥0akzky = \sum_{k \ge 0} a_k z^k gives (k+2)(k+1) ak+2−2k ak+2λ ak=0,soak+2=2(k−λ)(k+2)(k+1) ak.(k + 2)(k + 1)\, a_{k+2} - 2 k\, a_k + 2 \lambda\, a_k = 0, \quad \text{so} \quad a_{k+2} = \frac{2 (k - \lambda)}{(k + 2)(k + 1)}\, a_k. The values a0a_0 and a1a_1 are free, and every solution is an entire function. If λ=n\lambda = n is a nonnegative integer, the recurrence stops at k=nk = n for the series of the same parity as nn. This gives a polynomial solution of degree nn, a multiple of the Hermite polynomial HnH_n.

Remarks

For n=2n = 2, H2(z)=4z2−2H_2(z) = 4 z^2 - 2; then y′′=8y'' = 8 and y′=8zy' = 8 z, and 8−2z⋅8z+4(4z2−2)=08 - 2 z \cdot 8 z + 4 (4 z^2 - 2) = 0. The substitution y=ez2/2uy = e^{z^2 / 2} u links the equation to the quantum harmonic oscillator u′′+(2λ+1−z2)u=0u'' + (2 \lambda + 1 - z^2) u = 0. The point ∞\infty is an irregular singular point.

Further reading

  1. Web https://en.wikipedia.org/wiki/Hermite_polynomials
About this page
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Kindexample
WritingW0 stub
MSC34B30, 33C45, 34A25
IllustratesOrdinary point and singular point, Power series solution
Changed2 November 2026

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