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Algebraic topology Definition

Homotopy extension property

Builds on HomotopySubspace topology

Definition

Let XX be a topological space, let A⊆XA \subseteq X carry the subspace topology, let YY be a topological space, and let I=[0,1]I = [0, 1]. Let f ⁣:X→Yf \colon X \to Y be continuous, and let h ⁣:A×I→Yh \colon A \times I \to Y be a homotopy with h(a,0)=f(a)h(a, 0) = f(a) for all a∈Aa \in A. An extension of hh along ff is a homotopy H ⁣:X×I→YH \colon X \times I \to Y such that:

  1. H(x,0)=f(x)H(x, 0) = f(x) for all x∈Xx \in X;
  2. H(a,t)=h(a,t)H(a, t) = h(a, t) for all a∈Aa \in A and t∈It \in I.

The pair (X,A)(X, A) has the homotopy extension property with respect to YY if every such hh has an extension along every such ff. The pair (X,A)(X, A) has the homotopy extension property if it has it with respect to every topological space YY.

Remarks

If AA is closed in XX, then (X,A)(X, A) has the homotopy extension property if and only if X×{0}∪A×IX \times \set{0} \cup A \times I is a retract of X×IX \times I. Example: (Dn,Sn−1)(D^n, S^{n-1}) has it, because the radial projection from the point (0,…,0,2)(0, \ldots, 0, 2) of ℝn+1\R^{n+1} gives a retraction of Dn×ID^n \times I onto Dn×{0}∪Sn−1×ID^n \times \set{0} \cup S^{n-1} \times I. Non-example: let X={0}∪{1/n:n≥1}X = \set{0} \cup \set{1/n : n \ge 1} and A={0}A = \set{0}. A retraction rr of X×IX \times I onto X×{0}∪A×IX \times \set{0} \cup A \times I would fix (0,1)(0, 1), and would send each connected set {1/n}×I\set{1/n} \times I to (1/n,0)(1/n, 0). Then r(1/n,1)=(1/n,0)→(0,0)≠r(0,1)r(1/n, 1) = (1/n, 0) \to (0, 0) \neq r(0, 1), so rr is not continuous and the pair fails the property. Every CW pair has the homotopy extension property.

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To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Homotopy concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Homotopy_extension_property
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DefinesHomotopy extension property
UsesHomotopy, Subspace topology
Changed2 November 2026

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