Math 2.0

Algebraic topology Definition

Homotopy lifting property

Builds on HomotopyContinuous functionTopological space

Definition

Let EE, BB and XX be topological spaces, let p ⁣:E→Bp \colon E \to B be a continuous map, and let I=[0,1]I = [0, 1]. The map pp has the homotopy lifting property with respect to XX if the following holds. For every continuous map f~ ⁣:X→E\tilde f \colon X \to E and every homotopy H ⁣:X×I→BH \colon X \times I \to B with H(x,0)=p(f~(x))H(x, 0) = p(\tilde f(x)) for all x∈Xx \in X, there is a homotopy H~ ⁣:X×I→E\tilde H \colon X \times I \to E such that:

  1. p∘H~=Hp \circ \tilde H = H.
  2. H~(x,0)=f~(x)\tilde H(x, 0) = \tilde f(x) for all x∈Xx \in X.

Remarks

Example: every covering map has the homotopy lifting property with respect to every space, and the lift is then unique. For XX a point this is the path lifting property: for p ⁣:ℝ→S1p \colon \R \to S^1, p(t)=e2πitp(t) = e^{2\pi i t}, the loop H(t)=e2πitH(t) = e^{2\pi i t} with starting point 00 lifts to H~(t)=t\tilde H(t) = t.

Non-example: let E={0,1}E = \set{0, 1} with the discrete topology, B=[0,1]B = [0, 1] and pp the inclusion. For XX a point, f~=0\tilde f = 0 and H(t)=tH(t) = t, clauses 1 and 2 would force H~\tilde H to be a path in EE from 00 to 11, but EE is not path-connected.

In diagram form: every commutative square with X→EX \to E on top, X×{0}↪X×IX \times \set{0} \hookrightarrow X \times I on the left and pp on the right has a diagonal X×I→EX \times I \to E making both triangles commute. A map with this property for all spaces XX is a Hurewicz fibration; for all cubes InI^n, a Serre fibration.

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  1. Continuous function concept
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  4. Homotopy lifting property definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Homotopy_lifting_property
About this page
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Kinddefinition
WritingW0 stub
MSC55R05, 55P05
DefinesHomotopy lifting property
UsesHomotopy, Continuous function, Topological space
Changed2 November 2026

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