Math 2.0

Measure and integration Definition

Inner regular measure

Builds on Borel measureCompact set

Definition

Let XX be a topological space and let μ\mu be a Borel measure on XX. A Borel set A⊆XA \subseteq X is inner regular for μ\mu if μ(A)=sup⁡{μ(K):K⊆A, K compact and Borel}.\mu(A) = \sup \set{\mu(K) : K \subseteq A, \ K \text{ compact and Borel}}. The measure μ\mu is inner regular if every Borel set is inner regular for μ\mu.

Remarks

In a Hausdorff space every compact set is closed, hence Borel, so the condition "Borel" on KK is automatic.

Example: counting measure on ℝ\R is inner regular. If AA is finite, take K=AK = A; if AA is infinite, its finite subsets are compact and have arbitrarily large counting measure, so the supremum is ∞=μ(A)\infty = \mu(A).

Non-example: let XX be an uncountable set with the cocountable topology, whose open sets are ∅\emptyset and the complements of countable sets. Its Borel sets are the countable sets and their complements; let μ\mu be 00 on countable sets and 11 on the others. Compact subsets of XX are finite, so they have measure 00, while μ(X)=1\mu(X) = 1; thus μ\mu is not inner regular.

Variants: some authors approximate by closed sets instead of compact sets, and some ask inner regularity only for open sets.

Reading path

To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Borel measure concept
  2. Compact set concept
  3. Inner regular measure definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Regular_measure
About this page
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DefinesInner regular measure
UsesBorel measure, Compact set
Changed2 November 2026

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