Math 2.0

definition

Inverse Laplace transform

Definition

Let aa be a real number and let FF be a complex function on the half-plane {s∈C:Re⁡s>a}\{s \in \mathbb{C} : \operatorname{Re} s > a\}. An inverse Laplace transform of FF is a piecewise continuous function f:[0,∞)→Cf : [0, \infty) \to \mathbb{C} with two properties. First, there are constants M,bM, b with ∣f(t)∣≤Mebt|f(t)| \le M e^{b t} for t≥0t \ge 0. Second, the Laplace transform of ff equals F(s)F(s) for each ss with Re⁡s>max⁡(a,b)\operatorname{Re} s > \max(a, b). The notation is f=L−1{F}f = \mathcal{L}^{-1}\{F\}.

Remarks

By Lerch's theorem, two such functions with the same transform agree at each point where both are continuous. So L−1{F}\mathcal{L}^{-1}\{F\} is unique in practice, and unique among continuous functions. Let γ\gamma be a real number larger than the real parts of all singularities of FF. Under suitable conditions, the Bromwich integral recovers ff: f(t)=12πilim⁡T→∞∫γ−iTγ+iTestF(s) dsf(t) = \frac{1}{2 \pi i} \lim_{T \to \infty} \int_{\gamma - iT}^{\gamma + iT} e^{s t} F(s)\, ds. In practice, one splits FF into partial fractions and reads the inverse of each term from a table. For example, L−1{1/(s−a)}=eat\mathcal{L}^{-1}\{1/(s - a)\} = e^{a t}.

Explanations

L1 human

The inverse transform goes back from the ss side to the time side. After we solve a problem in terms of F(s)F(s), the inverse transform gives the solution as a function of time.

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Sources

  1. Web https://en.wikipedia.org/wiki/Inverse_Laplace_transform, lead section
  2. Web https://en.wikipedia.org/wiki/Inverse_Laplace_transform, Bromwich's inverse formula