Math 2.0

Functional analysis Definition

JB-algebra

Builds on Jordan algebraNormed vector spaceComplete metric space

Definition

Let AA be a Jordan algebra over ℝ\R, with product (a,b)↦a∘b(a, b) \mapsto a \circ b, and write a2=a∘aa^2 = a \circ a. A JB-algebra structure on AA is a norm ∥⋅∥\norm{\cdot} on AA such that for all a,b∈Aa, b \in A:

  1. AA is complete for the metric ∥a−b∥\norm{a - b};
  2. ∥a∘b∥≤∥a∥∥b∥\norm{a \circ b} \le \norm{a} \norm{b};
  3. ∥a2∥=∥a∥2\norm{a^2} = \norm{a}^2;
  4. ∥a2∥≤∥a2+b2∥\norm{a^2} \le \norm{a^2 + b^2}.

Remarks

Example: the real symmetric n×nn \times n matrices with a∘b=12(ab+ba)a \circ b = \frac{1}{2}(ab + ba) and the operator norm. Clause 1 holds in finite dimension, and clause 2 follows from ∥ab∥≤∥a∥∥b∥\norm{ab} \le \norm{a}\norm{b}. For clauses 3 and 4, ∥a∥\norm{a} is the largest absolute value of an eigenvalue, so ∥a2∥=∥a∥2\norm{a^2} = \norm{a}^2, and a2≤a2+b2a^2 \le a^2 + b^2 as positive semidefinite matrices.

Non-example: ℝ2\R^2 with the componentwise product and the norm ∥(x1,x2)∥=∣x1∣+∣x2∣\norm{(x_1, x_2)} = \abs{x_1} + \abs{x_2} fails clause 3. For a=(1,1)a = (1, 1) one has ∥a2∥=2\norm{a^2} = 2 but ∥a∥2=4\norm{a}^2 = 4. With the norm max⁡(∣x1∣,∣x2∣)\max(\abs{x_1}, \abs{x_2}) instead, it is a JB-algebra.

The self-adjoint part of a C*-algebra, with a∘b=12(ab+ba)a \circ b = \frac{1}{2}(ab + ba), is a JB-algebra.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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  1. Complete metric space concept
  2. Jordan algebra concept
  3. Normed vector space concept
  4. JB-algebra definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Jordan_operator_algebra
About this page
TagFG5909C0W5
URIm2://FG5909C0W5
Kinddefinition
WritingW0 stub
MSC46L70, 17C65, 46H70
DefinesJB-algebra
UsesJordan algebra, Normed vector space, Complete metric space
Changed3 November 2026

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