Math 2.0

Optics, electromagnetic theory Definition

Laser rate equations

Builds on Solution of an ordinary differential equation

Definition

Consider a single-mode laser with an ideal four-level gain medium. Let N(t)≥0N(t) \ge 0 be the population inversion density and ϕ(t)≥0\phi(t) \ge 0 the photon density in the cavity. Let Rp≥0R_p \ge 0 be the pump rate and B>0B > 0 the coefficient of stimulated emission. Let τ>0\tau > 0 be the lifetime of the upper laser level and τc>0\tau_c > 0 the photon lifetime in the cavity. The laser rate equations, without spontaneous emission into the mode, are the system of ordinary differential equations dNdt=Rp−Nτ−BNϕ,dϕdt=BNϕ−ϕτc.\frac{dN}{dt} = R_p - \frac{N}{\tau} - B N \phi, \qquad \frac{d\phi}{dt} = B N \phi - \frac{\phi}{\tau_c}.

Remarks

The steady states give the threshold. A steady state with ϕ>0\phi > 0 needs BN=1/τcB N = 1/\tau_c, so N=Nth=1/(Bτc)N = N_{\mathrm{th}} = 1/(B \tau_c). The first equation then gives ϕ=τc(Rp−Nth/τ)\phi = \tau_c (R_p - N_{\mathrm{th}}/\tau), which is positive exactly when Rp>Nth/τR_p > N_{\mathrm{th}}/\tau, the threshold pump rate. Above threshold the inversion is clamped at NthN_{\mathrm{th}} and the photon density grows linearly with the pump. Below threshold the only steady state is ϕ=0\phi = 0, N=RpτN = R_p \tau.

Example: with τc=1\tau_c = 1, τ=1\tau = 1, B=1B = 1 and Rp=3R_p = 3, the threshold is Nth=1N_{\mathrm{th}} = 1 and the steady state is N=1N = 1, ϕ=2\phi = 2; one checks 3−1−2=03 - 1 - 2 = 0 and 2−2=02 - 2 = 0.

Non-example: the equations do not track the phase of the field or the polarization of the medium. So they cannot describe effects such as the Lorenz-type chaos of the Maxwell–Bloch equations. Many variants exist, for example with a term for spontaneous emission into the mode or for three-level media.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Rate_equation
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MSC78A60, 34C60
DefinesLaser rate equations
UsesSolution of an ordinary differential equation
Changed3 November 2026

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