Math 2.0

Group theory and generalizations Example

Laver table

Builds on Self-distributive operationLarge cardinal

Example

For n≥0n \ge 0, the Laver table AnA_n is the set {1,2,…,2n}\set{1, 2, \dots, 2^n} with the unique binary operation ⋆\star such that:

  1. p⋆1=p+1p \star 1 = p + 1 for p<2np < 2^n, and 2n⋆1=12^n \star 1 = 1;
  2. p⋆(q⋆r)=(p⋆q)⋆(p⋆r)p \star (q \star r) = (p \star q) \star (p \star r) for all p,q,rp, q, r.

So AnA_n is a shelf: clause 2 is left self-distributivity. The table can be computed row by row from the bottom, where row 2n2^n is 2n⋆q=q2^n \star q = q. For p<2np < 2^n one uses p⋆(q+1)=(p⋆q)⋆(p+1)p \star (q + 1) = (p \star q) \star (p + 1), where p⋆q>pp \star q > p lies in a row already known.

For n=2n = 2 this gives the table of A2A_2, with pp indexing rows and qq indexing columns:

⋆\star 1 2 3 4
1 2 4 2 4
2 3 4 3 4
3 4 4 4 4
4 1 2 3 4

Check of one instance of clause 2: 1⋆(2⋆1)=1⋆3=21 \star (2 \star 1) = 1 \star 3 = 2, and (1⋆2)⋆(1⋆1)=4⋆2=2(1 \star 2) \star (1 \star 1) = 4 \star 2 = 2. All 6464 instances of clause 2 hold in A2A_2. The shelf A2A_2 is not a rack, since the row of 11 takes only the values 22 and 44.

Remarks

Each row of AnA_n is periodic, and its period is a power of 22. Laver proved that, if a rank-into-rank large cardinal exists, then the period of the row of 11 in AnA_n tends to infinity as nn grows. No proof of this statement in ZFC alone is known. The period of the row of 11 grows extremely slowly: it is 22 in A2A_2 and 44 in A3A_3. Dougherty showed that the least nn for which it reaches 3232, if there is one, is enormous.

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To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Large cardinal concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Laver_table
About this page
Tag9H65YDXMGJ
URIm2://9H65YDXMGJ
Kindexample
WritingW0 stub
MSC20N02, 03E55
Instance ofShelf
UsesSelf-distributive operation, Large cardinal
Same as
Changed2 November 2026

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