Math 2.0

Manifolds and cell complexes Definition

Lie group action

Builds on Lie groupSmooth manifoldGroup actionSmooth function

Definition

Let GG be a Lie group with identity ee and let MM be a smooth manifold. A (left) Lie group action of GG on MM is a map α ⁣:G×M→M\alpha \colon G \times M \to M, written α(g,p)=g⋅p\alpha(g, p) = g \cdot p, such that:

  1. e⋅p=pe \cdot p = p for all p∈Mp \in M;
  2. g⋅(h⋅p)=(gh)⋅pg \cdot (h \cdot p) = (gh) \cdot p for all g,h∈Gg, h \in G and p∈Mp \in M;
  3. α\alpha is smooth.

Remarks

Clauses 1 and 2 say that α\alpha is a group action; clause 3 is the smoothness condition. Right actions are defined in the same way with (p⋅h)⋅g=p⋅(hg)(p \cdot h) \cdot g = p \cdot (hg).

Example: SO(2)SO(2) acts on ℝ2\R^2 by A⋅v=AvA \cdot v = Av. The identity matrix fixes every vector, (AB)v=A(Bv)(AB)v = A(Bv), and the map (A,v)↦Av(A, v) \mapsto Av is polynomial in the entries, hence smooth.

Non-example: let G=ℝG = \R act on M=ℝM = \R by t⋅x=(x3+t)1/3t \cdot x = (x^3 + t)^{1/3}, with the real cube root. This is a group action, since s⋅(t⋅x)=(x3+t+s)1/3s \cdot (t \cdot x) = (x^3 + t + s)^{1/3}, and it is continuous. It is not smooth: the map t↦t⋅0=t1/3t \mapsto t \cdot 0 = t^{1/3} is not differentiable at t=0t = 0.

Each gg acts by a diffeomorphism of MM with inverse given by g−1g^{-1}.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Group action concept
  2. Lie group concept
  3. Smooth function concept
  4. Smooth manifold concept
  5. Lie group action definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Lie_group_action
About this page
TagGC7T4VW3N1
URIm2://GC7T4VW3N1
Kinddefinition
WritingW0 stub
MSC57S20, 22F05, 22E15
DefinesLie group action
UsesLie group, Smooth manifold, Group action, Smooth function
Changed2 November 2026

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