Math 2.0

Nonassociative rings and algebras Definition

Lie superalgebra

Builds on SuperalgebraLie algebraVector space

Definition

Let kk be a field of characteristic 00. Let ๐”ค=๐”ค0ห‰โŠ•๐”ค1ห‰\mathfrak{g} = \mathfrak{g}_{\bar 0} \oplus \mathfrak{g}_{\bar 1} be a vector space over kk graded by โ„ค/2โ„ค={0ห‰,1ห‰}\Z/2\Z = \set{\bar 0, \bar 1}. For a homogeneous element xโˆˆ๐”คax \in \mathfrak{g}_{a} write โˆฃxโˆฃ=a\abs{x} = a, the parity of xx. A Lie superalgebra structure on ๐”ค\mathfrak{g} is a bilinear map [โ‹…,โ‹…]โ€‰โฃ:๐”คร—๐”คโ†’๐”ค[\cdot, \cdot] \colon \mathfrak{g} \times \mathfrak{g} \to \mathfrak{g} such that for all homogeneous x,y,zx, y, z:

  1. [๐”คa,๐”คb]โІ๐”คa+b[\mathfrak{g}_a, \mathfrak{g}_b] \subseteq \mathfrak{g}_{a + b} for all a,bโˆˆโ„ค/2โ„คa, b \in \Z/2\Z;
  2. [x,y]=โˆ’(โˆ’1)โˆฃxโˆฃโˆฃyโˆฃ[y,x][x, y] = -(-1)^{\abs{x}\abs{y}} [y, x];
  3. (โˆ’1)โˆฃxโˆฃโˆฃzโˆฃ[x,[y,z]]+(โˆ’1)โˆฃyโˆฃโˆฃxโˆฃ[y,[z,x]]+(โˆ’1)โˆฃzโˆฃโˆฃyโˆฃ[z,[x,y]]=0(-1)^{\abs{x}\abs{z}} [x, [y, z]] + (-1)^{\abs{y}\abs{x}} [y, [z, x]] + (-1)^{\abs{z}\abs{y}} [z, [x, y]] = 0.

Remarks

Example: let V=V0ห‰โŠ•V1ห‰V = V_{\bar 0} \oplus V_{\bar 1} with V0ห‰=kmV_{\bar 0} = k^m and V1ห‰=knV_{\bar 1} = k^n. The space ๐”ค๐”ฉ(mโˆฃn)=Endโกk(V)\mathfrak{gl}(m|n) = \End_k(V), graded by the maps that preserve or swap the two parts, with [x,y]=xyโˆ’(โˆ’1)โˆฃxโˆฃโˆฃyโˆฃyx[x, y] = xy - (-1)^{\abs{x}\abs{y}} yx on homogeneous elements, is a Lie superalgebra. Clause 1 holds because parities add under composition, and clauses 2 and 3 follow from the associativity of composition by expanding the signed products.

Non-example: take the same graded space ๐”ค๐”ฉ(1โˆฃ1)\mathfrak{gl}(1|1) but the ordinary commutator [x,y]=xyโˆ’yx[x, y] = xy - yx. For the odd elements x=E12x = E_{12} and y=E21y = E_{21}, clause 2 requires [x,y]=[y,x][x, y] = [y, x], but xyโˆ’yx=E11โˆ’E22xy - yx = E_{11} - E_{22} while yxโˆ’xy=E22โˆ’E11yx - xy = E_{22} - E_{11}. So clause 2 fails.

The even part ๐”ค0ห‰\mathfrak{g}_{\bar 0} is an ordinary Lie algebra, and the bracket makes ๐”ค1ห‰\mathfrak{g}_{\bar 1} a ๐”ค0ห‰\mathfrak{g}_{\bar 0}-module. A Lie superalgebra with ๐”ค1ห‰=0\mathfrak{g}_{\bar 1} = 0 is just a Lie algebra. Over fields of characteristic 33 one adds the axiom [y,[y,y]]=0[y, [y, y]] = 0 for odd yy, and characteristic 22 needs a separate treatment.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Lie_superalgebra
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TagYJ0XRYN91F
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Kinddefinition
WritingW0 stub
MSC17B70, 17B60
DefinesLie superalgebra
UsesSuperalgebra, Lie algebra, Vector space
Changed3 November 2026

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