Math 2.0

Associative rings and algebras Definition

Near-ring

Builds on GroupSemigroup

Definition

A (right) near-ring is a set NN with two binary operations ++ and ⋅\cdot such that:

  1. (N,+)(N, +) is a group, not necessarily abelian, with identity element 00.
  2. (N,⋅)(N, \cdot) is a semigroup: (a⋅b)⋅c=a⋅(b⋅c)(a \cdot b) \cdot c = a \cdot (b \cdot c) for all a,b,c∈Na, b, c \in N.
  3. (a+b)⋅c=a⋅c+b⋅c(a + b) \cdot c = a \cdot c + b \cdot c for all a,b,c∈Na, b, c \in N.

Remarks

A left near-ring asks instead c⋅(a+b)=c⋅a+c⋅bc \cdot (a + b) = c \cdot a + c \cdot b; the two notions are mirror images. Every ring is a near-ring. Example: for a group (G,+)(G, +), let M(G)M(G) be the set of all maps G→GG \to G, with (f+g)(x)=f(x)+g(x)(f + g)(x) = f(x) + g(x) and f⋅g=f∘gf \cdot g = f \circ g. Clause 1 holds pointwise, clause 2 because composition is associative, and clause 3 because ((f+g)∘h)(x)=f(h(x))+g(h(x))((f + g) \circ h)(x) = f(h(x)) + g(h(x)). The other distributive law fails in M(ℤ)M(\Z): for the constant map f=1f = 1, f∘(g+h)=1f \circ (g + h) = 1 but f∘g+f∘h=2f \circ g + f \circ h = 2. Non-example: ℕ={0,1,2,…}\N = \set{0, 1, 2, \ldots} with the usual operations satisfies clauses 2 and 3, but fails clause 1, since 11 has no additive inverse.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Binary operation definition
  2. Group concept
  3. Associativity definition
  4. Semigroup definition
  5. Near-ring definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Near-ring
About this page
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Kinddefinition
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MSC16Y30
DefinesNear-ring
UsesGroup, Semigroup
Changed2 November 2026

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