Math 2.0

Operator theory Definition

Nuclear operator

Builds on Banach spaceContinuous linear mapContinuous dual spaceCompact operatorFinite-rank operatorTrace class operator

Definition

Let XX and YY be Banach spaces over ℝ\R or ℂ\C, and let X′X' be the continuous dual of XX. A bounded linear map T ⁣:X→YT \colon X \to Y is nuclear if there are sequences (fn)(f_n) in X′X' and (yn)(y_n) in YY such that ∑n=1∞∥fn∥∥yn∥<∞andTx=∑n=1∞fn(x) ynfor all x∈X.\sum_{n=1}^{\infty} \norm{f_n} \norm{y_n} < \infty \quad \text{and} \quad T x = \sum_{n=1}^{\infty} f_n(x) \, y_n \quad \text{for all } x \in X. The nuclear norm ν(T)\nu(T) is the infimum of ∑n∥fn∥∥yn∥\sum_n \norm{f_n} \norm{y_n} over all such representations.

Remarks

Every finite-rank operator is nuclear, with a finite sum. Example: on ℓ2\ell^2, let Tx=∑ndnxnenT x = \sum_n d_n x_n e_n with ∑n∣dn∣<∞\sum_n \abs{d_n} < \infty; take fn(x)=dnxnf_n(x) = d_n x_n and yn=eny_n = e_n, so ∥fn∥∥yn∥=∣dn∣\norm{f_n} \norm{y_n} = \abs{d_n} is summable and TT is nuclear. Non-example: the identity of an infinite-dimensional Banach space is not nuclear, because it is not compact. Every nuclear operator is a norm limit of the partial sums, which are of finite rank, so it is compact. When XX and YY are Hilbert spaces, the nuclear operators are exactly the trace class operators, and ν(T)\nu(T) is the trace norm.

Reading path

To understand this page from the ground up, read these 7 pages in order. The foundations come first.

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  1. Banach space concept
  2. Compact operator concept
  3. Continuous dual space concept
  4. Continuous linear map concept
  5. Finite-rank operator concept
  6. Trace class operator concept
  7. Nuclear operator definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Nuclear_operator
About this page
Tag3F94J43P2C
URIm2://3F94J43P2C
Kinddefinition
WritingW0 stub
MSC47B10, 46B28
DefinesNuclear operator
UsesBanach space, Continuous linear map, Continuous dual space, Compact operator, Finite-rank operator, Trace class operator
Changed2 November 2026

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