Math 2.0

Sequences, series, summability Definition

Rate of convergence

Builds on Real sequenceLimit of a sequence

Definition

Let (xk)k≥0(x_k)_{k \ge 0} be a real sequence that converges to a limit LL, with xk≠Lx_k \ne L for all kk. Let ek=∣xk−L∣e_k = \abs{x_k - L} be the error at step kk.

  1. The sequence converges linearly with rate μ\mu if lim⁡k→∞ek+1/ek=μ\lim_{k \to \infty} e_{k+1} / e_k = \mu for some μ∈(0,1)\mu \in (0, 1).
  2. It converges superlinearly if lim⁡k→∞ek+1/ek=0\lim_{k \to \infty} e_{k+1} / e_k = 0, and sublinearly if lim⁡k→∞ek+1/ek=1\lim_{k \to \infty} e_{k+1} / e_k = 1.
  3. For a real number q>1q > 1, it converges with order qq if lim⁡k→∞ek+1/ekq=μ\lim_{k \to \infty} e_{k+1} / e_k^q = \mu for some μ>0\mu > 0.

Order 22 is called quadratic convergence and order 33 cubic convergence. The same definitions apply to sequences in a normed space, with ek=∥xk−L∥e_k = \norm{x_k - L}.

Remarks

Example: xk=2−kx_k = 2^{-k} tends to 00, and ek+1/ek=1/2e_{k+1} / e_k = 1/2, so it converges linearly with rate 1/21/2. Example: xk=2−2kx_k = 2^{-2^k} tends to 00, and ek+1/ek2=2−2k+1/2−2k+1=1e_{k+1} / e_k^2 = 2^{-2^{k+1}} / 2^{-2^{k+1}} = 1, so it converges quadratically. Non-example of clause 1: xk=1/(k+1)x_k = 1/(k+1) tends to 00, but ek+1/ek=(k+1)/(k+2)→1e_{k+1} / e_k = (k+1)/(k+2) \to 1, so it converges only sublinearly. These notions are often called Q-linear and Q-quadratic convergence, where Q stands for "quotient". A weaker notion, R-convergence, asks only that ek≤εke_k \le \varepsilon_k for some sequence (εk)(\varepsilon_k) that tends to 00 with the given order.

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  1. Limit of a sequence concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Rate_of_convergence
About this page
TagT34R8Q0FJD
URIm2://T34R8Q0FJD
Kinddefinition
WritingW0 stub
MSC40A05, 65B99
DefinesRate of convergence
UsesReal sequence, Limit of a sequence
Changed2 November 2026

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