Math 2.0

Commutative algebra Definition

Regular sequence

Builds on Commutative ringModule over a ringZero divisor

Definition

Let RR be a commutative ring and let MM be an RR-module. A sequence x1,…,xnx_1, \ldots, x_n of elements of RR is an MM-regular sequence if:

  1. for each i=1,…,ni = 1, \ldots, n, the element xix_i is a non-zero-divisor on M/(x1,…,xi−1)MM / (x_1, \ldots, x_{i-1}) M, that is, xim=0x_i m = 0 in this quotient implies m=0m = 0 in it;
  2. M/(x1,…,xn)M≠0M / (x_1, \ldots, x_n) M \ne 0.

A regular sequence of RR is an RR-regular sequence.

Remarks

Example: in R=K[x1,…,xn]R = K[x_1, \ldots, x_n] with KK a field, the variables form a regular sequence, since R/(x1,…,xi−1)≅K[xi,…,xn]R/(x_1, \ldots, x_{i-1}) \cong K[x_i, \ldots, x_n] is a domain in which xi≠0x_i \ne 0, and R/(x1,…,xn)≅K≠0R/(x_1, \ldots, x_n) \cong K \ne 0. Non-example: in K[x,y]K[x, y] the sequence x,xyx, xy fails clause 1, because xyxy is zero in K[x,y]/(x)K[x,y]/(x) and so kills the nonzero element 11. A sequence that satisfies only clause 1 is called weakly regular. The order matters in general: in K[x,y,z]K[x, y, z], the sequence x,y(1−x),z(1−x)x, y(1-x), z(1-x) is regular but y(1−x),z(1−x),xy(1-x), z(1-x), x is not. If RR is a Noetherian local ring, MM is finitely generated and all xix_i lie in the maximal ideal, then every permutation of an MM-regular sequence is MM-regular.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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  1. Commutative ring concept
  2. Module over a ring concept
  3. Zero divisor concept
  4. Regular sequence definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Regular_sequence
About this page
Tag6D8RK0Q6QM
URIm2://6D8RK0Q6QM
Kinddefinition
WritingW0 stub
MSC13D02, 13C15
DefinesRegular sequence
UsesCommutative ring, Module over a ring, Zero divisor
Changed2 November 2026

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