Math 2.0

Algebraic topology Definition

Relative homotopy

Builds on HomotopySubspace topology

Definition

Let XX and YY be topological spaces and let A⊆XA \subseteq X. Let f,g ⁣:X→Yf, g \colon X \to Y be continuous maps with f(a)=g(a)f(a) = g(a) for all a∈Aa \in A. A homotopy from ff to gg relative to AA is a homotopy HH from ff to gg with H(a,t)=f(a)H(a, t) = f(a) for all a∈Aa \in A and t∈[0,1]t \in [0, 1]. The maps ff and gg are homotopic relative to AA, written f≃g (rel A)f \simeq g \ (\mathrm{rel}\ A), if such a homotopy exists.

Remarks

For A=∅A = \emptyset this is an ordinary homotopy. Being homotopic relative to AA is an equivalence relation on the continuous maps X→YX \to Y that agree with a given map on AA. Example: for X=[0,1]X = [0, 1], A={0,1}A = \set{0, 1}, Y=ℝ2Y = \R^2, and two paths f,gf, g with f(0)=g(0)f(0) = g(0) and f(1)=g(1)f(1) = g(1), the map H(s,t)=(1−t)f(s)+tg(s)H(s, t) = (1 - t) f(s) + t g(s) is a homotopy relative to AA, since H(0,t)=f(0)H(0, t) = f(0) and H(1,t)=f(1)H(1, t) = f(1). Non-example: in ℝ2∖{0}\R^2 \setminus \set{0}, the upper and lower half circles from (1,0)(1, 0) to (−1,0)(-1, 0) are homotopic as maps, since [0,1][0, 1] is contractible, but they are not homotopic relative to {0,1}\set{0, 1}.

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To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Homotopy concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Homotopy
About this page
TagHJEFC4CC6M
URIm2://HJEFC4CC6M
Kinddefinition
WritingW0 stub
MSC55Q05, 55P10
DefinesRelative homotopy
UsesHomotopy, Subspace topology
Changed2 November 2026

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