Math 2.0

Commutative algebra Definition

Residue field

Builds on Local ringQuotient ringFieldLocalization at a prime ideal

Definition

Let (R,π”ͺ)(R, \mathfrak m) be a local ring. The residue field of RR is the quotient ring k=R/π”ͺk = R/\mathfrak m. It is a field because π”ͺ\mathfrak m is a maximal ideal.

Let RR be a commutative ring and 𝔭\mathfrak p a prime ideal. The residue field of RR at 𝔭\mathfrak p is the residue field ΞΊ(𝔭)=R𝔭/𝔭R𝔭\kappa(\mathfrak p) = R_{\mathfrak p} / \mathfrak p R_{\mathfrak p} of the localization of RR at 𝔭\mathfrak p.

Remarks

The field ΞΊ(𝔭)\kappa(\mathfrak p) is isomorphic to the field of fractions of the integral domain R/𝔭R/\mathfrak p.

Example: the residue field of β„€(p)\Z_{(p)} is β„€/pβ„€\Z/p\Z, since a/b↦abβˆ’1β€Šmodβ€Špa/b \mapsto a b^{-1} \bmod p is a surjection with kernel pβ„€(p)p\Z_{(p)}. The residue field of k[ ⁣[x] ⁣]k[\![x]\!] is kk, by taking the constant term. For R=β„€R = \Z, the residue field at (0)(0) is β„š\Q and the residue field at pβ„€p\Z is β„€/pβ„€\Z/p\Z.

Non-example: in the local ring ℀(p)\Z_{(p)}, the quotient ℀(p)/p2℀(p)≅℀/p2℀\Z_{(p)}/p^2\Z_{(p)} \cong \Z/p^2\Z is not a field, because p≠0p \ne 0 there and p⋅p=0p \cdot p = 0. Only the quotient by the maximal ideal is a field.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Field concept
  2. Local ring concept
  3. Localization at a prime ideal concept
  4. Quotient ring concept
  5. Residue field definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Residue_field
About this page
Tag8ST7CTZ2DE
URIm2://8ST7CTZ2DE
Kinddefinition
WritingW0 stub
MSC13H99, 13B30
DefinesResidue field
UsesLocal ring, Quotient ring, Field, Localization at a prime ideal
Changed2 November 2026

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