Math 2.0

Real functions Definition

Schur-convex function

Builds on MajorizationPermutation

Definition

Let n≥1n \ge 1. For x∈ℝnx \in \R^n, let x[1]≥x[2]≥⋯≥x[n]x_{[1]} \ge x_{[2]} \ge \dots \ge x_{[n]} be the entries of xx in decreasing order. A vector y∈ℝny \in \R^n majorizes x∈ℝnx \in \R^n, written x≺yx \prec y, if ∑i=1kx[i]≤∑i=1ky[i]for k=1,…,n−1,∑i=1nx[i]=∑i=1ny[i];\sum_{i=1}^{k} x_{[i]} \le \sum_{i=1}^{k} y_{[i]} \quad \text{for } k = 1, \dots, n - 1, \qquad \sum_{i=1}^{n} x_{[i]} = \sum_{i=1}^{n} y_{[i]}; see majorization. A function f ⁣:ℝn→ℝf \colon \R^n \to \R is Schur-convex if f(x)≤f(y)f(x) \le f(y) for all x,y∈ℝnx, y \in \R^n with x≺yx \prec y. It is Schur-concave if −f-f is Schur-convex.

Remarks

A Schur-convex function is symmetric: if yy is obtained from xx by a permutation of the entries, then x≺yx \prec y and y≺xy \prec x, so f(x)=f(y)f(x) = f(y). Every symmetric convex function is Schur-convex. For a symmetric ff with continuous partial derivatives on ℝn\R^n, the Schur–Ostrowski criterion says that ff is Schur-convex if and only if (xi−xj)(∂if(x)−∂jf(x))≥0(x_i - x_j)\big(\partial_i f(x) - \partial_j f(x)\big) \ge 0 for all xx and all i,ji, j.

Example: f(x)=max⁡ixi=x[1]f(x) = \max_i x_i = x_{[1]}. If x≺yx \prec y, the case k=1k = 1 of the definition gives x[1]≤y[1]x_{[1]} \le y_{[1]}, so f(x)≤f(y)f(x) \le f(y).

Non-example: f(x1,x2)=x1f(x_1, x_2) = x_1 on ℝ2\R^2. The vectors (1,0)(1, 0) and (0,1)(0, 1) majorize each other, but f(1,0)=1>0=f(0,1)f(1, 0) = 1 > 0 = f(0, 1).

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  1. Majorization concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Schur-convex_function
About this page
Tag24CEMRAGJ8
URIm2://24CEMRAGJ8
Kinddefinition
WritingW0 stub
MSC26B25, 26D15
DefinesSchur-convex function
UsesMajorization, Permutation
Changed2 November 2026

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