Math 2.0

Associative rings and algebras Modules and ideals Lemma

Schur's lemma

Builds on Module over a ringSimple module

Statement

Let RR be a ring and let MM and NN be simple left RR-modules. Let f ⁣:M→Nf \colon M \to N be a homomorphism of RR-modules. Then either f=0f = 0 or ff is an isomorphism.

Remarks

The kernel of ff is a submodule of MM, so it is 00 or MM. The image of ff is a submodule of NN, so it is 00 or NN. If f≠0f \ne 0, the kernel is not MM and the image is not 00, so ff is injective and surjective. Example: a nonzero group homomorphism ℤ/pℤ→ℤ/pℤ\Z/p\Z \to \Z/p\Z, for pp prime, is a bijection. Simplicity is needed: the map ℤ/4ℤ→ℤ/4ℤ\Z/4\Z \to \Z/4\Z, x↦2xx \mapsto 2x, is nonzero and not an isomorphism. A common form concerns an algebraically closed field kk, a kk-algebra AA, and a simple AA-module MM of finite dimension over kk. Then every endomorphism of MM is multiplication by a scalar.

Going deeper

For a student

Schur's lemma is the first tool of representation theory. It shows that the endomorphism ring of a simple module is a division ring. For representations of a group over ℂ\C it gives that the endomorphisms of an irreducible representation are scalars. This is the key step in the orthogonality relations for characters and in the decomposition of semisimple modules into isotypic parts.

Reading path

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  1. Module over a ring definition
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Where this leads

4 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Schur%27s_lemma
About this page
TagX4M2FFKQJ6
URIm2://X4M2FFKQJ6
Kindstatement, lemma
WritingW0 stub
MSC16D60, 20C05
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AboutSimple module
UsesModule over a ring, Simple module
Same as
Changed2 November 2026

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