Math 2.0

Algebraic topology Definition

Serre fibration

Builds on Homotopy lifting propertyContinuous functionTopological space

Definition

Let EE and BB be topological spaces and let p ⁣:E→Bp \colon E \to B be a continuous map. Let I=[0,1]I = [0, 1]. The map pp is a Serre fibration if it has the homotopy lifting property with respect to the cube InI^n for every integer n≥0n \ge 0. That is, let n≥0n \ge 0, let f~ ⁣:In→E\tilde f \colon I^n \to E be continuous, and let H ⁣:In×I→BH \colon I^n \times I \to B be continuous with H(x,0)=p(f~(x))H(x, 0) = p(\tilde f(x)) for all xx. Then there is a continuous H~ ⁣:In×I→E\tilde H \colon I^n \times I \to E with p∘H~=Hp \circ \tilde H = H and H~(x,0)=f~(x)\tilde H(x, 0) = \tilde f(x) for all x∈Inx \in I^n.

Remarks

Example: for spaces BB and FF, the projection p ⁣:B×F→Bp \colon B \times F \to B is a Serre fibration. Given f~=(f1,f2)\tilde f = (f_1, f_2) and HH, the map H~(x,t)=(H(x,t),f2(x))\tilde H(x, t) = (H(x, t), f_2(x)) is a lift with the right start.

Non-example: the inclusion p ⁣:{0}→[0,1]p \colon \set{0} \to [0, 1] is not a Serre fibration. Take n=0n = 0, f~\tilde f the map to 00 and H(t)=tH(t) = t; any lift would satisfy p(H~(1))=1p(\tilde H(1)) = 1, but the only point of {0}\set{0} maps to 00.

Equivalently, pp has the homotopy lifting property with respect to all CW complexes. Every Hurewicz fibration is a Serre fibration, and every fiber bundle is a Serre fibration.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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  1. Continuous function concept
  2. Homotopy lifting property concept
  3. Topological space concept
  4. Serre fibration definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Fibration
About this page
Tag9KE5E84M3M
URIm2://9KE5E84M3M
Kinddefinition
WritingW0 stub
MSC55R05
DefinesSerre fibration
UsesHomotopy lifting property, Continuous function, Topological space
Changed2 November 2026

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