Math 2.0

example

Sum of the reciprocals of the factorials

Example

The series ∑n=0∞1n!=1+1+12+16+124+⋯\sum_{n=0}^{\infty} \frac{1}{n!} = 1 + 1 + \frac{1}{2} + \frac{1}{6} + \frac{1}{24} + \cdots converges, and its sum is the number e ≈2.71828\approx 2.71828.

Remarks

The series converges by the ratio test, since the ratio of consecutive terms is 1/(n+1)→01/(n+1) \to 0. It is the value at x=1x = 1 of the power series ∑xn/n!\sum x^n / n! of the exponential function. The series converges fast. The tail after the term 1/N!1/N! is less than 1/(N! N)1/(N! \, N).

Explanations

L1 human

The terms shrink very fast, because n!n! grows fast. Only a few terms give a good value of ee: the first five terms already give 2.7082.708.

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Sources

  1. Web https://en.wikipedia.org/wiki/E_(mathematical_constant), Definitions