Math 2.0

Operator theory Definition

Unbounded operator

Builds on Normed vector spaceLinear subspaceLinear mapContinuous linear map

Definition

Let XX and YY be normed spaces over ℝ\R or ℂ\C. An unbounded operator (or linear operator) TT from XX to YY is a pair consisting of

  1. a linear subspace D(T)D(T) of XX, the domain of TT, and
  2. a linear map T ⁣:D(T)→YT \colon D(T) \to Y.

Two such operators SS and TT are equal when D(S)=D(T)D(S) = D(T) and Sx=TxSx = Tx for all x∈D(T)x \in D(T). The operator TT is an extension of SS, written S⊆TS \subseteq T, when D(S)⊆D(T)D(S) \subseteq D(T) and Tx=SxTx = Sx for all x∈D(S)x \in D(S).

Remarks

Example: on X=Y=L2(0,1)X = Y = L^2(0, 1), let D(T)D(T) be the space of continuously differentiable functions on [0,1][0, 1], and let Tf=f′Tf = f'. This is linear, so TT is an unbounded operator. It is not bounded: fn(x)=sin⁡(nπx)f_n(x) = \sin(n \pi x) has ∥fn∥=1/2\norm{f_n} = 1/\sqrt{2}, while ∥Tfn∥=nπ/2\norm{T f_n} = n \pi / \sqrt{2}.

Non-example: the rule f↦f′f \mapsto f' is not an operator with domain all of L2(0,1)L^2(0, 1), since many elements of L2(0,1)L^2(0, 1) have no derivative in L2(0,1)L^2(0, 1).

Every continuous linear map X→YX \to Y is an unbounded operator with domain XX; the word "unbounded" means "not necessarily bounded". Sums and products are defined on the natural domains: D(S+T)=D(S)∩D(T)D(S + T) = D(S) \cap D(T) and D(ST)={x∈D(T):Tx∈D(S)}D(ST) = \set{x \in D(T) : Tx \in D(S)}.

Reading path

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  1. Continuous linear map concept
  2. Linear map concept
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  4. Normed vector space concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Unbounded_operator, Definitions and basic properties
About this page
TagM9HEZ5X3FX
URIm2://M9HEZ5X3FX
Kinddefinition
WritingW1 stated
MSC47A05, 47B25
DefinesUnbounded operator
UsesNormed vector space, Linear subspace, Linear map, Continuous linear map
Changed2 November 2026

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