Math 2.0

Integral equations Definition

Volterra integral equation

Builds on Riemann integral

Definition

Let a<ba < b, let Δ={(t,s):a≤s≤t≤b}\Delta = \set{(t, s) : a \le s \le t \le b}, let K ⁣:Δ→ℝK \colon \Delta \to \R be continuous, and let f ⁣:[a,b]→ℝf \colon [a, b] \to \R be continuous. A linear Volterra integral equation of the first kind is f(t)=∫atK(t,s) x(s) ds,t∈[a,b].f(t) = \int_a^t K(t, s) \, x(s) \, ds, \quad t \in [a, b]. A linear Volterra integral equation of the second kind is x(t)=f(t)+λ∫atK(t,s) x(s) ds,t∈[a,b],x(t) = f(t) + \lambda \int_a^t K(t, s) \, x(s) \, ds, \quad t \in [a, b], with a constant λ\lambda. In both, x ⁣:[a,b]→ℝx \colon [a, b] \to \R is the unknown continuous function and KK is the kernel. The upper limit of the integral is the variable tt.

Remarks

Example: x(t)=1+∫0tx(s) dsx(t) = 1 + \int_0^t x(s) \, ds on [0,b][0, b], second kind with K=1K = 1 and λ=1\lambda = 1. The function x=etx = e^t solves it, since 1+∫0tes ds=et1 + \int_0^t e^s \, ds = e^t.

Non-example: x(t)=f(t)+∫abK(t,s)x(s) dsx(t) = f(t) + \int_a^b K(t, s) x(s) \, ds has a fixed upper limit bb; it is a Fredholm integral equation, not a Volterra one.

For the second kind, the solution exists and is unique for every λ\lambda. It is the sum of the Neumann series x=∑j≥0λjVjfx = \sum_{j \ge 0} \lambda^j V^j f, where (Vx)(t)=∫atK(t,s)x(s) ds(V x)(t) = \int_a^t K(t, s) x(s) \, ds; the bound ∣(Vjf)(t)∣≤∥K∥∞j(t−a)j∥f∥∞/j!\abs{(V^j f)(t)} \le \norm{K}_\infty^j (t - a)^j \norm{f}_\infty / j! makes it converge. The same scheme gives existence for nonlinear equations x(t)=f(t)+∫atK(t,s,x(s)) dsx(t) = f(t) + \int_a^t K(t, s, x(s)) \, ds with KK Lipschitz in xx, which include the integral form of initial value problems.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Volterra_integral_equation
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Changed2 November 2026

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