Math 2.0

Differential geometry Definition

Willmore flow

Builds on Willmore energyMean curvatureGaussian curvatureLaplace–Beltrami operator

Definition

Let Σ\Sigma be a closed oriented surface and let T>0T > 0. Let f ⁣:Σ×[0,T)→ℝ3f \colon \Sigma \times [0, T) \to \R^3 be a smooth family of immersions, and write ft=f(⋅,t)f_t = f(\cdot, t). For each tt, let ν\nu be the unit normal of ftf_t. Let H=12(κ1+κ2)H = \tfrac{1}{2}(\kappa_1 + \kappa_2) be the mean curvature of ftf_t with respect to ν\nu, so that the mean curvature vector is 2Hν2H\nu. Let KK be the Gaussian curvature of ftf_t. Let Δ\Delta be the Laplace–Beltrami operator of the metric induced by ftf_t. The family is a solution of the Willmore flow if ∂f∂t=−(ΔH+2H(H2−K))ν.\frac{\partial f}{\partial t} = -\left(\Delta H + 2H\left(H^2 - K\right)\right) \nu.

Remarks

The right side is minus the L2L^2 gradient of the Willmore energy W(ft)=∫ΣH2 dAW(f_t) = \int_\Sigma H^2 \, dA, so W(ft)W(f_t) does not increase. Example: the constant family of a round sphere of radius rr is a solution. Indeed H=±1/rH = \pm 1/r is constant, so ΔH=0\Delta H = 0, and H2−K=1/r2−1/r2=0H^2 - K = 1/r^2 - 1/r^2 = 0, so the right side vanishes. Non-example: the spheres of radius 1+t1 + t do not form a solution, since the right side vanishes for each of them but the surfaces move. A surface for which ΔH+2H(H2−K)=0\Delta H + 2H(H^2 - K) = 0 is a Willmore surface; these are exactly the stationary solutions. The equation is of fourth order and parabolic, so the maximum principle fails and convexity need not be preserved.

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  1. Gaussian curvature concept
  2. Laplace–Beltrami operator concept
  3. Mean curvature concept
  4. Willmore energy concept
  5. Willmore flow definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Willmore_energy
About this page
TagCMK92XDD0W
URIm2://CMK92XDD0W
Kinddefinition
WritingW0 stub
MSC53E40, 53A05
DefinesWillmore flow
UsesWillmore energy, Mean curvature, Gaussian curvature, Laplace–Beltrami operator
Changed2 November 2026

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