Math 2.0

Differential geometry Definition

Yamabe flow

Builds on Riemannian metricScalar curvature

Definition

Let MM be a smooth manifold and let T>0T > 0. Let (g(t))0≤t<T(g(t))_{0 \le t < T} be a smooth family of Riemannian metrics on MM. It solves the Yamabe flow if ∂g∂t=−Rg(t) g(t),\frac{\partial g}{\partial t} = -R_{g(t)}\, g(t), where Rg(t)R_{g(t)} is the scalar curvature of g(t)g(t).

Let MM be compact. The normalized Yamabe flow is ∂g∂t=(rg(t)−Rg(t))g(t),\frac{\partial g}{\partial t} = \left(r_{g(t)} - R_{g(t)}\right) g(t), where rg(t)r_{g(t)} is the average of Rg(t)R_{g(t)} over MM with respect to the volume of g(t)g(t). It preserves the total volume.

Remarks

Example: on the unit sphere SnS^n with n≥2n \ge 2 and round metric g0g_0, put g(t)=ρ(t)g0g(t) = \rho(t) g_0. The scalar curvature of g0g_0 is n(n−1)n(n-1), so that of g(t)g(t) is n(n−1)/ρ(t)n(n-1)/\rho(t). The equation becomes ρ′(t)g0=−n(n−1)g0\rho'(t) g_0 = -n(n-1) g_0, which holds for ρ(t)=1−n(n−1)t\rho(t) = 1 - n(n-1)t with 0≤t<1/(n(n−1))0 \le t < 1/(n(n-1)). Non-example: the family g(t)=(1+t)g0g(t) = (1 + t) g_0 on the flat torus fails, since the scalar curvature is 00 but the metric changes. The right side is a multiple of gg. So a solution has the form g(t)=u(⋅,t) g(0)g(t) = u(\cdot, t)\, g(0) for a positive function uu on M×[0,T)M \times [0, T), and it stays in the conformal class of g(0)g(0). In dimension 22 the Ricci curvature equals 12Rg\tfrac{1}{2} R g, so the Yamabe flow coincides with the Ricci flow ∂g/∂t=−2Ric⁡\partial g/\partial t = -2 \operatorname{Ric}.

Reading path

To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Riemannian metric concept
  2. Scalar curvature concept
  3. Yamabe flow definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Yamabe_flow
About this page
TagFK4F02GMVA
URIm2://FK4F02GMVA
Kinddefinition
WritingW0 stub
MSC53E20, 53C21
DefinesYamabe flow
UsesRiemannian metric, Scalar curvature
Changed2 November 2026

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