Math 2.0

Real functions Definition

Caputo fractional derivative

Builds on Riemann–Liouville integralGamma functionHigher derivative

Definition

Let a<ba < b be real numbers and let α>0\alpha > 0 be a real number that is not an integer. Let n=⌈α⌉n = \ceil{\alpha}. Let f ⁣:[a,b]→ℝf \colon [a, b] \to \R have n−1n - 1 continuous derivatives such that f(n−1)f^{(n-1)} is absolutely continuous, so that f(n)f^{(n)} exists almost everywhere and is integrable. The Caputo fractional derivative of order α\alpha of ff is CDaαf(x)=1Γ(n−α)∫ax(x−t)n−α−1f(n)(t) dt,a<x≤b,{}^{C}D_a^\alpha f(x) = \frac{1}{\Gamma(n - \alpha)} \int_a^x (x - t)^{n - \alpha - 1} f^{(n)}(t) \, dt, \qquad a < x \le b, that is, the Riemann–Liouville integral Ian−αI_a^{n - \alpha} applied to the higher derivative f(n)f^{(n)}. Here Γ\Gamma is the gamma function. For an integer α=n\alpha = n, one sets CDanf=f(n){}^{C}D_a^n f = f^{(n)}.

Remarks

Example: let a=0a = 0, α=12\alpha = \tfrac{1}{2}, so n=1n = 1, and f(x)=xf(x) = x. Then f′=1f' = 1 and CD01/2f(x)=1Γ(1/2)∫0x(x−t)−1/2 dt=2xπ{}^{C}D_0^{1/2} f(x) = \frac{1}{\Gamma(1/2)} \int_0^x (x - t)^{-1/2} \, dt = \frac{2\sqrt{x}}{\sqrt{\pi}}. For a constant f=cf = c, f(n)=0f^{(n)} = 0 and the Caputo derivative is 00. Non-example: the Riemann–Liouville derivative ddxI01/21=1πx\frac{d}{dx} I_0^{1/2} 1 = \frac{1}{\sqrt{\pi x}} is not 00, so it does not agree with the Caputo derivative on constants. In general, under the hypotheses above, the Caputo derivative equals the Riemann–Liouville derivative of f(x)−∑k=0n−1f(k)(a)k!(x−a)kf(x) - \sum_{k=0}^{n-1} \frac{f^{(k)}(a)}{k!} (x - a)^k.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Caputo_fractional_derivative
About this page
TagBH5TK7DC2X
URIm2://BH5TK7DC2X
Kinddefinition
WritingW0 stub
MSC26A33
DefinesCaputo fractional derivative
UsesRiemann–Liouville integral, Gamma function, Higher derivative
Changed2 November 2026

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