Math 2.0

Fluid mechanics Definition

Dimensionless numbers in fluid mechanics

Builds on Fluid mechanics

Definition

Fix base dimensions, such as mass 𝖬\mathsf{M}, length 𝖫\mathsf{L}, time 𝖳\mathsf{T} and temperature Θ\Theta. Each positive physical quantity qq of a flow has a dimension [q]=𝖬a𝖫b𝖳cΘd[q] = \mathsf{M}^{a} \mathsf{L}^{b} \mathsf{T}^{c} \Theta^{d} with rational exponents a,b,c,da, b, c, d. Let q1,…,qnq_1, \dots, q_n be quantities of the flow and let k1,…,knk_1, \dots, k_n be rational numbers. The product Ξ =q1k1β‹―qnkn\Pi = q_1^{k_1} \cdots q_n^{k_n} is a dimensionless number if all the exponents of [Ξ ]=[q1]k1β‹―[qn]kn[\Pi] = [q_1]^{k_1} \cdots [q_n]^{k_n} are zero.

Remarks

The value of a dimensionless number does not change when the units of the base dimensions are changed. Example: with density ρ\rho, speed UU, length LL and dynamic viscosity ΞΌ\mu, [ρUL/ΞΌ]=(π–¬π–«βˆ’3)(π–«π–³βˆ’1)(𝖫)/(π–¬π–«βˆ’1π–³βˆ’1)=1[\rho U L / \mu] = (\mathsf{M} \mathsf{L}^{-3})(\mathsf{L} \mathsf{T}^{-1})(\mathsf{L}) / (\mathsf{M} \mathsf{L}^{-1} \mathsf{T}^{-1}) = 1, so ρUL/ΞΌ\rho U L / \mu is dimensionless; it is the Reynolds number. Non-example: ρUL\rho U L has dimension π–¬π–«βˆ’1π–³βˆ’1\mathsf{M} \mathsf{L}^{-1} \mathsf{T}^{-1}, so it is not dimensionless. Most dimensionless numbers of fluid mechanics are ratios of two forces, two time scales or two transport rates.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Dimensionless_numbers_in_fluid_mechanics
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DefinesDimensionless numbers in fluid mechanics
UsesFluid mechanics
Changed3 November 2026

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