statement theorem
Existence of the infimum
Statement
Let be a nonempty subset of the real numbers that is bounded below. Then has an infimum in .
Remarks
Proof: the set is nonempty and bounded above. By the completeness axiom, it has a supremum . Then is the infimum of . Another proof: the set of lower bounds of is nonempty and bounded above by each element of , and its supremum is .
Explanations
L1 human
If a set of real numbers has a floor, then it has a highest floor. This follows from the completeness axiom by a reflection of the number line through , which turns floors into ceilings.
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- no evidence level
- Real numbers object
- Set bounded above definition
- Infimum definition
- Supremum definition
- Completeness axiom statement
- Existence of the infimum statement
Sources
- Web https://en.wikipedia.org/wiki/Least-upper-bound_property, Statement for real numbers
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