Combinatorics Coloring Counterexample
Hedetniemi's conjecture
Builds on GraphChromatic numberGraph homomorphismComplete graph
Counterexample
Let and be finite graphs. Their tensor product has vertex set . In it, is adjacent to when is an edge of and is an edge of . Hedetniemi's conjecture asserted that for all finite graphs and , where is the chromatic number. The conjecture is false: in 2019 Yaroslav Shitov constructed finite graphs and with
Remarks
The inequality always holds. Indeed, the projection is a graph homomorphism to , so a proper colouring of pulls back to one of . The same holds for . Shitov's counterexample uses an exponential graph. For a graph and , the vertices of are all maps . Two maps and are adjacent when for every edge of , in both orders of and . The map is a proper colouring of with colours. Indeed, if and are adjacent, then is an edge and is adjacent to , so . So any with and is a counterexample, and Shitov showed that such exist for large . The conjecture holds when ; the case is a theorem of El-Zahar and Sauer.
Reading path
To understand this page from the ground up, read these 7 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Complete graph example
- Graph definition
- Graph colouring definition
- Graph homomorphism definition
- K-colourable graph definition
- Chromatic number definition
- Hedetniemi's conjecture counterexample
Further reading
About this page
| Tag | PE207P2DZD |
|---|---|
| URI | m2://PE207P2DZD |
| Kind | counterexample |
| Writing | W0 stub |
| MSC | 05C15, 05C76 |
| Uses | Graph, Chromatic number, Graph homomorphism, Complete graph |
| Changed | 2 November 2026 |
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