statement proposition
K5 and K3,3 are not planar
Statement
The complete graph and the complete bipartite graph are not planar.
Remarks
The graph has vertices and edges. The edge bound for planar graphs allows at most edges. The graph has vertices and edges, and it has no cycle of length . The bound allows at most edges. The statement for is the three utilities problem: three houses cannot each be joined to three utilities without crossings.
Explanations
L1 human
Try to join each of three houses to each of three utilities with lines that never cross. It is impossible, and the reason is a count of edges and faces.
What this node needs for W1
- an inventory row: the row of the inventory that the node accounts for (0 of 1)
The writing levels say how complete the text of a node is. They do not measure its truth.
What this needs
To read this node, read these 10 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Complete bipartite graph example
- Complete graph example
- Graph definition
- Planar graph definition
- Walk definition
- Reachability definition
- Connected graph definition
- Euler's formula for planar graphs statement
- Edge bound for planar graphs statement
- K5 and K3,3 are not planar statement
What depends on this
1 node uses this node, directly or through other nodes.
- Kuratowski's theorem 0J6G5NJC5R
Sources
- Web https://en.wikipedia.org/wiki/Three_utilities_problem, Unsolvability
What links here
Used by
- Kuratowski's theorem 0J6G5NJC5R