Math 2.0

Mechanics of particles and systems Statics Proposition

Lami's theorem

Builds on Mechanical equilibrium

Statement

Let three nonzero forces FAF_A, FBF_B, FCF_C in a plane act at one point, not all along one line. Suppose they are in equilibrium, that is, FA+FB+FC=0F_A + F_B + F_C = 0. Let α\alpha be the angle between FBF_B and FCF_C, β\beta the angle between FCF_C and FAF_A, and γ\gamma the angle between FAF_A and FBF_B. Then ∣FA∣sin⁡α=∣FB∣sin⁡β=∣FC∣sin⁡γ.\frac{\abs{F_A}}{\sin\alpha} = \frac{\abs{F_B}}{\sin\beta} = \frac{\abs{F_C}}{\sin\gamma}.

Remarks

Proof idea: placing the three vectors head to tail gives a closed triangle, since they sum to zero. The interior angle of this triangle opposite the side FAF_A is π−α\pi - \alpha, and similarly for the others. The law of sines and sin⁡(π−α)=sin⁡α\sin(\pi - \alpha) = \sin\alpha give the result. The hypotheses ensure that no two of the forces are parallel, so all three angles lie strictly between 00 and π\pi and the sines are nonzero.

Example: a weight of WW newtons hangs from two strings that each make an angle of 60∘60^\circ with the vertical. The angle between the two strings is 120∘120^\circ and each string makes 180∘−60∘=120∘180^\circ - 60^\circ = 120^\circ with the downward weight. So W/sin⁡120∘=T/sin⁡120∘W / \sin 120^\circ = T / \sin 120^\circ, and each string tension TT equals WW.

Going deeper

For a student

Lami's theorem is the law of sines applied to the triangle of forces. It is a special case of the equilibrium conditions of statics for concurrent forces, where the torque condition is automatic. For more than three forces, or forces not meeting at one point, one uses the full equilibrium equations instead.

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  1. Mechanical equilibrium concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Lami%27s_theorem
About this page
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URIm2://KTFS80Y2PC
Kindstatement, proposition
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AboutMechanical equilibrium
UsesMechanical equilibrium
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Changed3 November 2026

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