Mechanics of particles and systems Statics Proposition
Lami's theorem
Builds on Mechanical equilibrium
Statement
Let three nonzero forces , , in a plane act at one point, not all along one line. Suppose they are in equilibrium, that is, . Let be the angle between and , the angle between and , and the angle between and . Then
Remarks
Proof idea: placing the three vectors head to tail gives a closed triangle, since they sum to zero. The interior angle of this triangle opposite the side is , and similarly for the others. The law of sines and give the result. The hypotheses ensure that no two of the forces are parallel, so all three angles lie strictly between and and the sines are nonzero.
Example: a weight of newtons hangs from two strings that each make an angle of with the vertical. The angle between the two strings is and each string makes with the downward weight. So , and each string tension equals .
Going deeper
For a student
Lami's theorem is the law of sines applied to the triangle of forces. It is a special case of the equilibrium conditions of statics for concurrent forces, where the torque condition is automatic. For more than three forces, or forces not meeting at one point, one uses the full equilibrium equations instead.
Reading path
To understand this page from the ground up, read these 2 pages in order. The foundations come first.
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- no evidence level
- Mechanical equilibrium concept
- Lami's theorem statement
Further reading
About this page
| Tag | KTFS80Y2PC |
|---|---|
| URI | m2://KTFS80Y2PC |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 70C20 |
| Status | This copy of the site has no build data. Run m2 status KTFS80Y2PC. |
| About | Mechanical equilibrium |
| Uses | Mechanical equilibrium |
| Same as | |
| Changed | 3 November 2026 |
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