Math 2.0

Algebraic topology Definition

Mapping cylinder

Builds on Quotient topologyDisjoint union topologyProduct topologyContinuous map

Definition

Let XX and YY be topological spaces, let I=[0,1]I = [0, 1], and let f ⁣:X→Yf \colon X \to Y be a continuous map. The mapping cylinder of ff is the space Mf=((X×I)⊔Y)/∼,M_f = \bigl( (X \times I) \sqcup Y \bigr) / \sim, where X×IX \times I has the product topology and ⊔\sqcup is the disjoint union. The relation ∼\sim is the smallest equivalence relation with (x,1)∼f(x)(x, 1) \sim f(x) for all x∈Xx \in X. The space MfM_f carries the quotient topology.

Remarks

The map j ⁣:X→Mfj \colon X \to M_f, x↦[(x,0)]x \mapsto [(x, 0)], is an embedding, and YY embeds in MfM_f as well. The map r ⁣:Mf→Yr \colon M_f \to Y with r[(x,t)]=f(x)r[(x, t)] = f(x) and r(y)=yr(y) = y is a homotopy equivalence, YY is a strong deformation retract of MfM_f, and f=r∘jf = r \circ j. Example: for YY a point, MfM_f is the cone CX=(X×I)/(X×{1})CX = (X \times I) / (X \times \set{1}). Example: for f=id⁡Xf = \id_X, MfM_f is homeomorphic to X×IX \times I. Non-example: the space (X×I)⊔Y(X \times I) \sqcup Y without the identification is not MfM_f; for XX and YY nonempty it is disconnected even when XX and YY are connected, while MfM_f is then connected.

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To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Continuous map concept
  2. Disjoint union topology concept
  3. Product topology concept
  4. Quotient topology concept
  5. Mapping cylinder definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Mapping_cylinder
About this page
TagV25YYE26M1
URIm2://V25YYE26M1
Kinddefinition
WritingW0 stub
MSC55P05, 54B17
DefinesMapping cylinder
UsesQuotient topology, Disjoint union topology, Product topology, Continuous map
Changed2 November 2026

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