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Statistical mechanics, structure of matter Definition

Maxwell–Boltzmann distribution

Builds on Kinetic theory of gasesNormal distribution

Definition

Let m>0m > 0 be the particle mass and k>0k > 0 the Boltzmann constant. Let n>0n > 0, u∈ℝ3u \in \R^3 and T>0T > 0. The Maxwell–Boltzmann distribution, or Maxwellian, with density nn, bulk velocity uu and temperature TT is the function M ⁣:ℝ3→(0,∞)M \colon \R^3 \to (0, \infty), M(v)=n(m2πkT)3/2exp⁡(−m∣v−u∣22kT).M(v) = n \left( \frac{m}{2\pi k T} \right)^{3/2} \exp\left( - \frac{m \abs{v - u}^2}{2 k T} \right). A local Maxwellian is a function f(t,x,v)=M(v)f(t, x, v) = M(v) in which nn, uu and TT depend on (t,x)(t, x).

Remarks

The function M/nM/n is the density of the normal distribution on ℝ3\R^3 with mean uu and covariance (kT/m)I(kT/m) I. In the kinetic description of a gas, MM has number density nn, bulk velocity uu and temperature TT. For u=0u = 0, the speed s=∣v∣s = \abs{v} has the density 4πs2(m/(2πkT))3/2e−ms2/(2kT)4\pi s^2 (m/(2\pi kT))^{3/2} e^{-ms^2/(2kT)} on (0,∞)(0, \infty), after normalising by nn. Its most probable value is 2kT/m\sqrt{2kT/m}, its mean is 8kT/(πm)\sqrt{8kT/(\pi m)}, and its root mean square is 3kT/m\sqrt{3kT/m}.

Example: check of the temperature for u=0u = 0. Each component viv_i has variance kT/mkT/m under M/nM/n, so ∫m2∣v∣2M dv=n⋅m2⋅3⋅kTm=32nkT\int \tfrac{m}{2} \abs{v}^2 M \, dv = n \cdot \tfrac{m}{2} \cdot 3 \cdot \tfrac{kT}{m} = \tfrac32 n k T, as required.

Non-example: the uniform distribution of velocities on a ball {∣v∣≤R}\set{\abs{v} \le R} is not a Maxwellian, since it vanishes outside the ball while every Maxwellian is positive everywhere.

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  1. Kinetic theory of gases concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Maxwell%E2%80%93Boltzmann_distribution
About this page
Tag3QM3WDNAT7
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Kinddefinition
WritingW0 stub
MSC82B40, 82C40, 76P05
DefinesMaxwell–Boltzmann distribution
UsesKinetic theory of gases, Normal distribution
Changed3 November 2026

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