Math 2.0

definition

Product of rings

Definition

Let II be a set and let (Ri)i∈I(R_i)_{i \in I} be a family of rings. The product ∏i∈IRi\prod_{i \in I} R_i is the set of families (ai)i∈I(a_i)_{i \in I} with ai∈Ria_i \in R_i for each i∈Ii \in I. Its addition is (ai)i∈I+(bi)i∈I=(ai+bi)i∈I(a_i)_{i \in I} + (b_i)_{i \in I} = (a_i + b_i)_{i \in I}. Its multiplication is (ai)i∈I⋅(bi)i∈I=(ai⋅bi)i∈I(a_i)_{i \in I} \cdot (b_i)_{i \in I} = (a_i \cdot b_i)_{i \in I}. With these operations, ∏i∈IRi\prod_{i \in I} R_i is a ring, with zero (0)i∈I(0)_{i \in I} and identity (1)i∈I(1)_{i \in I}.

Remarks

For two rings RR and SS, the product is R×S={(r,s):r∈R,s∈S}R \times S = \{(r, s) : r \in R, s \in S\}. For each j∈Ij \in I, the projection ∏i∈IRi→Rj\prod_{i \in I} R_i \to R_j, (ai)i∈I↦aj(a_i)_{i \in I} \mapsto a_j, is a ring homomorphism. The product of two nonzero rings is not an integral domain: in R×SR \times S, (1,0)⋅(0,1)=(0,0)(1, 0) \cdot (0, 1) = (0, 0).

Explanations

L1 human

To multiply two pairs, you multiply the first entries and the second entries apart. For example, in Z×Z\mathbb{Z} \times \mathbb{Z}, (2,3)⋅(4,5)=(8,15)(2, 3) \cdot (4, 5) = (8, 15).

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  1. Group concept
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Sources

  1. Web https://en.wikipedia.org/wiki/Product_of_rings, lead section