Math 2.0

Number theory Proof

Proof of the Fibonacci recurrence from the definition

Builds on Fibonacci sequence

Proof

  1. Let nn be a natural number.
  2. The node Fibonacci sequence defines (Fm)m≥0(F_m)_{m \ge 0} by F0=0F_0 = 0, F1=1F_1 = 1 and, for every natural number mm, Fm+2=Fm+1+FmF_{m+2} = F_{m+1} + F_m.
  3. Taking m=nm = n in this defining rule gives Fn+2=Fn+1+FnF_{n+2} = F_{n+1} + F_n, which is the claim.

Idea

The Fibonacci numbers are defined by their two starting values and this rule. So the recurrence holds by definition. Its use is that, with F0F_0 and F1F_1, it fixes every later term.

Reading path

To understand this page from the ground up, read these 2 pages in order. The foundations come first.

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  1. Fibonacci sequence example
  2. Proof of the Fibonacci recurrence from the definition proof

Where this leads

3 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Fibonacci_sequence, Definition
About this page
TagB35K99ADCP
URIm2://B35K99ADCP
Kindproof
WritingW0 stub
MSC11B39
ProvesFibonacci recurrence
UsesFibonacci sequence
Changed4 November 2026

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