Proof of the uniqueness of inverses
Proof
- Let be an element of a group with identity . Let and both be inverses of , so and .
- Then .
- By associativity, .
- Since , .
- Thus , and has only one inverse.
Idea
Multiply one inverse by the element and then by the other inverse. Associativity lets the product collapse in two ways.
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- Binary operation definition
- Group concept
- Identity element definition
- Inverse element definition
- Proof of the uniqueness of inverses proof
What depends on this
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- Inner automorphism group is isomorphic to G modulo its centre 05HYGWFG63
- Homomorphisms preserve identity and inverses 08FKQD7NJ3
- The kernel is a normal subgroup 0C9ZKYSPYR
- First isomorphism theorem 0CXXJNG5B6
- Uniqueness of inverses 0D9NDGE9KP
- A homomorphism is injective iff its kernel is trivial 0N2P0XRTDF
- Second isomorphism theorem 0PPP2J2DJV
- Order of the alternating group 0SZ1KMNWVE
- Third isomorphism theorem 0TJ1V9DDPC
- Proof that the kernel is a normal subgroup AY60KQR8RT
- Proof that a homomorphism is injective iff its kernel is trivial D05NAAC3XK
- Proof of the first isomorphism theorem H4QSPK0XTZ
Sources
- Web https://en.wikipedia.org/wiki/Group_(mathematics), Uniqueness of inverses
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