Mathematical logic and foundations Proof
Proof that the image of an intersection lies in the intersection of the images
Builds on Image of a setIntersectionSubset
Proof
We show that each element of the left side is an element of the right side.
- Let be a function and let .
- Let . By the definition of the image, there is with .
- By the definition of intersection, and .
- Since and , the definition of the image gives .
- Since and , the definition of the image gives .
- By steps 4 and 5, .
- Step 2 took an arbitrary element of . So is a subset of .
Idea
A point of that maps to is a witness in and a witness in at the same time. The reverse inclusion can fail, because may come from one point of and a different point of .
Reading path
To understand this page from the ground up, read these 17 pages in order. The foundations come first.
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- no evidence level
- Element definition
- Proposition concept
- Set definition
- Conjunction definition
- Implication definition
- Predicate definition
- Ordered pair definition
- Intersection definition
- Existential quantifier definition
- Universal quantifier definition
- Cartesian product definition
- Subset definition
- Uniqueness quantifier definition
- Binary relation definition
- Function definition
- Image of a set definition
- Proof that the image of an intersection lies in the intersection of the images proof
Where this leads
1 page builds on this one.
Further reading
About this page
| Tag | 3N7QBXTW9A |
|---|---|
| URI | m2://3N7QBXTW9A |
| Kind | proof |
| Writing | W0 stub |
| MSC | 03E20 |
| Proves | Image of an intersection |
| Uses | Image of a set, Intersection, Subset |
| Changed | 4 November 2026 |
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