Math 2.0

Number theory Diophantine approximation and transcendence Conjecture

Schanuel's conjecture

Builds on Complex exponentialLinear independenceTranscendental number

Statement

Let z1,…,znz_1, \dots, z_n be complex numbers that are linearly independent over ℚ\Q. Then the field ℚ(z1,…,zn,ez1,…,ezn)\Q(z_1, \dots, z_n, e^{z_1}, \dots, e^{z_n}) has transcendence degree at least nn over ℚ\Q. Here eze^{z} is the complex exponential. The transcendence degree of a field K⊇ℚK \supseteq \Q is the largest number of elements of KK that are algebraically independent over ℚ\Q.

Remarks

The conjecture is open. The case n=1n = 1 is known: if z≠0z \ne 0, then zz or eze^z is transcendental, which is the Hermite–Lindemann theorem. If z1,…,znz_1, \dots, z_n are algebraic, the conjecture gives the Lindemann–Weierstrass theorem, which is proved. With z1=1z_1 = 1 and z2=iπz_2 = i\pi, it would imply that ee and π\pi are algebraically independent; it is not even known whether e+πe + \pi is irrational. It would also imply the Gelfond–Schneider theorem and Baker's theorem, and even that ℚ\Q-linearly independent logarithms of algebraic numbers are algebraically independent.

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  1. Complex exponential concept
  2. Linear independence concept
  3. Transcendental number concept
  4. Schanuel's conjecture conjecture

Further reading

  1. Web https://en.wikipedia.org/wiki/Schanuel%27s_conjecture
About this page
Tag65PV4VFP9Y
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Kindconjecture
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MSC11J81, 11J85
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AboutTranscendental number, Complex exponential
UsesComplex exponential, Linear independence, Transcendental number
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Changed2 November 2026

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