Math 2.0

Linear and multilinear algebra; matrix theory Proposition

Solving a linear system with an inverse matrix

Builds on Invertible matrixSystem of linear equations

Statement

Let AA be an invertible matrix with inverse B=A−1B = A^{-1}. Then for each vector bb of the right size, the system of linear equations Ax=bAx = b is consistent. The vector x=Bbx = Bb is a solution of it. So the solution of Ax=bAx = b is given by x=A−1bx = A^{-1}b.

Remarks

The check is direct: A(Bb)=(AB)b=Ib=bA(Bb) = (AB)b = Ib = b. This is why an inverse, once known, solves every system with the same matrix AA. Uniqueness also holds, since Ax=bAx = b gives x=A−1Ax=A−1bx = A^{-1}Ax = A^{-1}b.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

Show the path as a graph
Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Invertible matrix concept
  2. Linear equation definition
  3. System of linear equations definition
  4. Solving a linear system with an inverse matrix statement

Further reading

  1. Web https://github.com/davidaustinm/ula/blob/b6ea263ef23703072b7007485bb7a2d89c5f399b/src/section3-1.xml#L525, src/section3-1.xml:525
About this page
Tag3RQX3T70NX
URIm2://3RQX3T70NX
Kindstatement, proposition
WritingW0 stub
MSC15A09
StatusThis copy of the site has no build data. Run m2 status 3RQX3T70NX.
AboutInvertible matrix
UsesInvertible matrix, System of linear equations
Changed4 November 2026

Markdown · JSON · Edit on GitHub

What this page needs for W1

  • an inventory row: the row of the inventory that the node accounts for (0 of 1)

The writing levels say how complete the text of a page is. They do not measure its truth.

What links here

No page links to this page yet.