Fluid mechanics Shock waves Example
Taylor–von Neumann–Sedov blast wave
Builds on Shock wave in gasesEuler equations
Example
An energy is released at a point at time in a polytropic gas at rest, of uniform density , with adiabatic exponent . Assume the pressure of the undisturbed gas is negligible, so the outgoing spherical shock wave is strong. Then the flow is a self-similar solution of the Euler equations. The shock radius is where is a dimensionless constant that depends only on . Behind the shock, the density, velocity and pressure are fixed profiles in the variable , scaled by powers of .
Check by dimensions: the only parameters are , of dimension mass times length squared over time squared, and , of dimension mass over length cubed. So has dimension length to the fifth power, and is the only length that can be formed from , and . The shock speed is , which decreases in time as the energy spreads over a growing volume.
Remarks
The profiles solve a system of ordinary differential equations, with the strong-shock Rankine–Hugoniot conditions at . Taylor, von Neumann and Sedov found this solution independently, and Sedov and von Neumann gave it in closed form. G. I. Taylor used the formula with published photographs of the first atomic explosion to estimate its energy. The solution stops being accurate at late times, when the shock weakens and the pressure of the undisturbed gas matters.
Reading path
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- Euler equations concept
- Shock wave in gases concept
- Taylor–von Neumann–Sedov blast wave example
Further reading
About this page
| Tag | XDSE93QMNM |
|---|---|
| URI | m2://XDSE93QMNM |
| Kind | example |
| Writing | W0 stub |
| MSC | 76L05, 76N15 |
| Instance of | Similarity solution |
| Uses | Shock wave in gases, Euler equations |
| Changed | 3 November 2026 |
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