Math 2.0

example

The cosets of a subgroup that is not normal do not form a group

Example

In the symmetric group S3S_3, let H={e,(1 2)}H = \{e, (1\,2)\}. Compose permutations from right to left. Two of the left cosets are (1 3)H={(1 3),(1 2 3)}(1\,3)H = \{(1\,3), (1\,2\,3)\} and (2 3)H={(2 3),(1 3 2)}(2\,3)H = \{(2\,3), (1\,3\,2)\}. Try to set (aH)(bH)=(ab)H(aH)(bH) = (ab)H. With a=(1 3)a = (1\,3) and b=(2 3)b = (2\,3), we get ab=(1 3 2)ab = (1\,3\,2), which is in (2 3)H(2\,3)H. With a=(1 2 3)a = (1\,2\,3) from the same coset, we get ab=(1 2)ab = (1\,2), which is in HH. The two results are in different cosets. Thus this product is not defined, and the cosets of HH do not form a quotient group.

Remarks

HH is not normal in S3S_3. For a normal subgroup the product of cosets is always defined.

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  1. Group concept
  2. Symmetric group concept
  3. Conjugate elements definition
  4. Subgroup definition
  5. Conjugate subgroup definition
  6. Left coset definition
  7. Right coset definition
  8. Normal subgroup definition
  9. Normality via left and right cosets statement
  10. Quotient group definition
  11. The cosets of a subgroup that is not normal do not form a group example

Sources

  1. Web https://en.wikipedia.org/wiki/Quotient_group, Definition