Math 2.0

Mechanics of deformable solids Definition

Transverse isotropy

Builds on Anisotropic elasticityElasticity tensor

Definition

Let CC be the elasticity tensor of a linear elastic material, and let ee be a unit vector. For a rotation QQ, let (Q⋆C)ijkl=QipQjqQkrQlsCpqrs(Q \star C)_{ijkl} = Q_{ip} Q_{jq} Q_{kr} Q_{ls} C_{pqrs}. The material is transversely isotropic with axis ee if Q⋆C=CQ \star C = C for every rotation QQ about the axis ee.

Remarks

Example: with axis e=e3e = e_3 and Voigt notation, the stiffness matrix of a transversely isotropic material has the form (C11C12C13000C12C11C13000C13C13C33000000C44000000C44000000C66),C66=12(C11−C12),\begin{pmatrix} C_{11} & C_{12} & C_{13} & 0 & 0 & 0 \\ C_{12} & C_{11} & C_{13} & 0 & 0 & 0 \\ C_{13} & C_{13} & C_{33} & 0 & 0 & 0 \\ 0 & 0 & 0 & C_{44} & 0 & 0 \\ 0 & 0 & 0 & 0 & C_{44} & 0 \\ 0 & 0 & 0 & 0 & 0 & C_{66} \end{pmatrix}, \qquad C_{66} = \tfrac{1}{2}(C_{11} - C_{12}), with the 55 independent constants C11,C12,C13,C33,C44C_{11}, C_{12}, C_{13}, C_{33}, C_{44}. Non-example: a cubic material has C11=C33C_{11} = C_{33}, C12=C13C_{12} = C_{13} and C66=C44C_{66} = C_{44}. If C44≠12(C11−C12)C_{44} \ne \tfrac{1}{2}(C_{11} - C_{12}), the rotation by π/4\pi/4 about e3e_3 changes CC. So such a cubic material is not transversely isotropic. An isotropic material is transversely isotropic for every axis; many authors exclude this case. The plane normal to ee is the plane of isotropy.

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  1. Anisotropic elasticity concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Transverse_isotropy
About this page
TagBP5C0B0W79
URIm2://BP5C0B0W79
Kinddefinition
WritingW0 stub
MSC74E10, 74B05
DefinesTransverse isotropy
UsesAnisotropic elasticity, Elasticity tensor
Changed3 November 2026

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