Math 2.0

concept

Work done by a force field

Summary

The work done by a force field FF on a particle that moves along a curve γ\gamma is the line integral W=∫γF⋅drW = \int_\gamma F \cdot d\mathbf{r}. Only the component of the force along the direction of motion contributes, positively when it points forward and negatively when it points backward.

Remarks

For a constant force FF and a straight displacement dd, the work is F⋅dF \cdot d. For a C1C^1 path, W=∫abF(γ(t))⋅γ′(t) dtW = \int_a^b F(\gamma(t)) \cdot \gamma'(t) \, dt. The integrand F⋅γ′F \cdot \gamma' is the power, the rate at which the force does work. If F=−∇UF = -\nabla U for a potential energy UU, then W=U(γ(a))−U(γ(b))W = U(\gamma(a)) - U(\gamma(b)), and the work does not depend on the path. Gravity near the surface of the Earth is an example. A force that is always orthogonal to the velocity does no work.

Explanations

L1 human

Work measures how much a force helps a motion. Pushing a box forward does positive work, pushing against its motion does negative work, and pushing straight down on a sliding box does no work.

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  1. Euclidean space object
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  6. Line integral of a vector field concept
  7. Work done by a force field concept

Sources

  1. Web https://en.wikipedia.org/wiki/Work_(physics), Work done by a variable force
  2. Web https://en.wikipedia.org/wiki/Work_(physics), Mathematical calculation