Math 2.0

statement proposition

A linear isometry preserves the inner product

Statement

Let VV and WW be inner product spaces over R\R or C\C, with the induced norms, and let T ⁣:V→WT \colon V \to W be a linear isometry. Then, for all u,v∈Vu, v \in V, ⟨T(u),T(v)⟩=⟨u,v⟩.\langle T(u), T(v) \rangle = \langle u, v \rangle.

Remarks

The proof applies the polarisation identity, which writes inner products in terms of norms. Conversely, a linear map that keeps inner products keeps norms. So a linear isometry also keeps angles and orthogonality.

Explanations

L1 human

If a linear map keeps lengths, then it also keeps angles. The reason is that lengths determine inner products, by polarisation. So rigid linear motions keep the whole geometry.

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  1. Vector space definition
  2. Inner product definition
  3. Linear map definition
  4. Norm definition
  5. Inner product space definition
  6. Normed vector space definition
  7. Linear isometry definition
  8. Norm induced by an inner product definition
  9. Polarisation identity statement
  10. A linear isometry preserves the inner product statement

Sources

  1. Web https://en.wikipedia.org/wiki/Isometry, Linear isometry