Math 2.0

statement theorem

Continuous dependence on initial data

Statement

Let JJ be an interval, let UU be an open subset of Rn\mathbb{R}^n, let K≥0K \ge 0, and let f:J×U→Rnf : J \times U \to \mathbb{R}^n be continuous. Assume that ∥f(t,x)−f(t,y)∥≤K∥x−y∥\|f(t, x) - f(t, y)\| \le K \|x - y\| for all t∈Jt \in J and x,y∈Ux, y \in U. Let a<ba < b with [a,b]⊆J[a, b] \subseteq J, and let γ1,γ2:[a,b]→U\gamma_1, \gamma_2 : [a, b] \to U be solutions of x′=f(t,x)x' = f(t, x). Then ∥γ1(t)−γ2(t)∥≤∥γ1(a)−γ2(a)∥ eK(t−a)for each t∈[a,b].\|\gamma_1(t) - \gamma_2(t)\| \le \|\gamma_1(a) - \gamma_2(a)\|\, e^{K (t - a)} \quad \text{for each } t \in [a, b].

Remarks

So the solution at time tt is a Lipschitz function of the initial value, with constant eK(t−a)e^{K(t - a)}. The proof applies Grönwall's inequality to u(t)=∥γ1(t)−γ2(t)∥u(t) = \|\gamma_1(t) - \gamma_2(t)\|. Existence, uniqueness and continuous dependence together make the initial value problem well posed, in the sense of Jacques Hadamard. For equal initial values, the bound gives uniqueness again.

Explanations

L1 human

If two solutions start close together, they stay close for a while. Their distance can grow, but at most exponentially, with rate given by the Lipschitz constant. So a small error in the initial value gives a small error in the solution over a bounded time.

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  1. Differential equation concept
  2. Function concept
  3. Interval concept
  4. Ordinary differential equation definition
  5. Lipschitz condition definition
  6. Grönwall's inequality statement
  7. Solution of an ordinary differential equation definition
  8. Continuous dependence on initial data statement

Sources

  1. Web https://en.wikipedia.org/wiki/Well-posed_problem, lead section
  2. Web https://en.wikipedia.org/wiki/Gr%C3%B6nwall%27s_inequality, Integral form for continuous functions