statement proposition
Dimension of the annihilator
Statement
Let be a field, let be a finite-dimensional vector space over , and let be a subspace of . Then where is the annihilator of .
Remarks
A proof extends a basis of to a basis of . Then the dual basis forms are a basis of . Another proof uses the isomorphism . With the double dual isomorphism, it gives in finite dimensions.
Explanations
L1 human
The more directions a subspace has, the fewer independent linear forms vanish on it. In , a line is killed by a plane of forms, and a plane is killed by a line of forms. The two dimensions always add up to the dimension of the space.
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What this needs
To read this node, read these 15 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Vector space definition
- Linear combination definition
- Linear map definition
- Linear subspace definition
- Linear independence definition
- Linear form definition
- Linear span definition
- Space of linear maps definition
- Dual space definition
- Spanning set definition
- Basis definition
- Annihilator of a subspace definition
- Finite-dimensional vector space definition
- Dimension definition
- Dimension of the annihilator statement
Sources
- Web https://en.wikipedia.org/wiki/Dual_space, Quotient spaces and annihilators
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