statement theorem
Existence of an orthonormal basis
Statement
Let be a finite-dimensional inner product space over or . Then has an orthonormal basis. Moreover, each orthonormal family in extends to an orthonormal basis of .
Remarks
The proof applies the Gram–Schmidt process to any basis of . For the extension, first extend the orthonormal family to a basis, and then apply Gram–Schmidt; it keeps the first vectors. Hence each finite-dimensional real inner product space is isometric to with the dot product.
Explanations
L1 human
Every finite-dimensional inner product space has a basis of perpendicular unit vectors. We construct one with the Gram–Schmidt process. So every such space looks like or with the standard inner product.
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What this needs
To read this node, read these 13 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Vector space definition
- Inner product definition
- Linear combination definition
- Linear subspace definition
- Orthogonal vectors definition
- Linear independence definition
- Linear span definition
- Orthonormal family definition
- Spanning set definition
- Basis definition
- Gram–Schmidt process concept
- Orthonormal basis definition
- Existence of an orthonormal basis statement
Sources
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