Math 2.0

example

Integers modulo n form a cyclic group

Example

Let n≥1n \ge 1. The integers modulo nn, Z/nZ={0,1,…,n−1}\mathbb{Z}/n\mathbb{Z} = \{0, 1, \dots, n-1\}, form a group under addition modulo nn. Each element kk is the sum 1+1+⋯+11 + 1 + \dots + 1 of kk copies of 11. Thus 11 is a generator, and the group is cyclic of order nn. Addition modulo nn is commutative, so the group is abelian. This agrees with the result that cyclic groups are abelian.

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  1. Group concept
  2. Integers modulo n concept
  3. Laws of exponents in a group statement
  4. Subgroup definition
  5. Cyclic subgroup generated by an element definition
  6. Cyclic group definition
  7. Integers modulo n form a cyclic group example

Sources

  1. Web https://en.wikipedia.org/wiki/Cyclic_group, Integer and modular addition