Math 2.0

Statistical mechanics, structure of matter Quantum spin chains and lattice fermions Theorem

Lieb–Schultz–Mattis theorem

Builds on Quantum Heisenberg model

Statement

Let SS be a half-odd-integer, let LL be an even integer, and let J>0J > 0. Let HL=J∑j=1L𝐒j⋅𝐒j+1H_L = J \sum_{j=1}^{L} \mathbf{S}_j \cdot \mathbf{S}_{j+1} be the antiferromagnetic spin-SS quantum Heisenberg model on a ring of LL sites, with 𝐒L+1=𝐒1\mathbf{S}_{L+1} = \mathbf{S}_1, and let E0(L)E_0(L) be its ground-state energy. Let ψL\psi_L be a ground state of HLH_L that is an eigenvector of the translation and of the total magnetization StotzS^z_{\mathrm{tot}} with eigenvalue 00. Then there is a constant CC, independent of LL, and a unit vector φL\varphi_L orthogonal to ψL\psi_L such that ⟨φL,HLφL⟩−E0(L)≤CL.\langle \varphi_L, H_L \varphi_L \rangle - E_0(L) \le \frac{C}{L}. Consequently, in the limit L→∞L \to \infty, either the ground state is degenerate or there is no spectral gap above it.

Remarks

The idea of the proof is a twist. Let ψ\psi be the ground state, which for the Heisenberg antiferromagnet on an even ring is a unique total-spin singlet invariant under translation up to a phase. Set U=exp⁡(2πiL∑jj Sjz)U = \exp\big(\tfrac{2\pi i}{L}\sum_{j} j\, S^z_j\big), which rotates the spins slowly along the chain. Each bond energy changes by O(1/L2)O(1/L^2), so ⟨Uψ,HLUψ⟩−E0(L)=O(1/L)\langle U\psi, H_L U\psi \rangle - E_0(L) = O(1/L). The translation TT satisfies TUT−1=Ue−2πiStotz/Le2πiS1zTUT^{-1} = U e^{-2\pi i S^z_{\mathrm{tot}}/L} e^{2\pi i S^z_1}, and e2πiS1z=−1e^{2\pi i S^z_1} = -1 for half-odd-integer SS; since Stotzψ=0S^z_{\mathrm{tot}}\psi = 0 and TψT\psi is a multiple of ψ\psi, this gives ⟨ψ,Uψ⟩=−⟨ψ,Uψ⟩\langle \psi, U\psi \rangle = -\langle \psi, U\psi \rangle, so φ=Uψ\varphi = U\psi is orthogonal to ψ\psi. Lieb, Schultz and Mattis proved the case S=12S = \tfrac12 in 1961, and Affleck and Lieb extended it to all half-odd-integer SS in 1986. The argument fails for integer SS, where e2πiS1z=1e^{2\pi i S^z_1} = 1, and indeed the spin-11 AKLT chain has a gap.

Going deeper

For a student

The result is a constraint from symmetry and filling: it relates translation symmetry, spin rotation symmetry and the half-integer spin per unit cell. For the spin-12\tfrac12 chain the exact solution confirms the gapless option. For integer spins the argument breaks down, and Haldane's prediction of a gap is consistent with it. Modern generalizations, by Oshikawa and by Hastings in higher dimensions, give similar constraints for lattices with a fractional filling per unit cell.

Reading path

To understand this page from the ground up, read these 6 pages in order. The foundations come first.

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  1. Bethe ansatz concept
  2. Lattice model concept
  3. Self-adjoint operator concept
  4. Tensor product of Hilbert spaces concept
  5. Quantum Heisenberg model example
  6. Lieb–Schultz–Mattis theorem statement

Where this leads

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Further reading

  1. Web https://en.wikipedia.org/wiki/Quantum_Heisenberg_model
About this page
TagZ0ZHN80F2B
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Kindstatement, theorem
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MSC82B20, 82B10, 82D40
StatusThis copy of the site has no build data. Run m2 status Z0ZHN80F2B.
AboutQuantum Heisenberg model
UsesQuantum Heisenberg model
Changed3 November 2026

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