Math 2.0

Fluid mechanics Definition

Speed of sound

Builds on Wave equationEuler equations

Definition

Let a fluid have an equation of state p=p(ρ,s)p = p(\rho, s). It gives the pressure pp in terms of the density ρ>0\rho > 0 and the specific entropy ss, with ∂p/∂ρ>0\partial p / \partial \rho > 0. The speed of sound in the state (ρ,s)(\rho, s) is the number c>0c > 0 with c2=(∂p∂ρ)s.c^2 = \left(\frac{\partial p}{\partial \rho}\right)_{s}. So c2c^2 is the derivative of the pressure with respect to the density at constant entropy.

Remarks

Linearise the compressible Euler equations about a fluid at rest with uniform density ρ0\rho_0. Then small perturbations p′p' of the pressure solve the wave equation ∂t2p′=c2Δp′\partial_t^2 p' = c^2 \Delta p', so they travel at speed cc. Example: for an ideal gas with constant ratio of specific heats γ\gamma, isentropic changes satisfy p=Kργp = K \rho^\gamma, so c2=γp/ρ=γRTc^2 = \gamma p / \rho = \gamma R T, with RR the specific gas constant and TT the temperature. For air, γ=1.4\gamma = 1.4 and R≈287 J/(kg K)R \approx 287\ \mathrm{J/(kg\,K)}, and at T=293 KT = 293\ \mathrm{K} this gives c≈343 m/sc \approx 343\ \mathrm{m/s}. Non-example: Newton's value (∂p/∂ρ)T=p/ρ≈290 m/s\sqrt{(\partial p / \partial \rho)_T} = \sqrt{p / \rho} \approx 290\ \mathrm{m/s} uses the derivative at constant temperature instead of constant entropy. It is too low, because sound waves are too fast for heat to flow between compressed and expanded regions.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Speed_of_sound
About this page
Tag67NQNMNRDF
URIm2://67NQNMNRDF
Kinddefinition
WritingW0 stub
MSC76N15, 76Q05
DefinesSpeed of sound
UsesWave equation, Euler equations
Changed3 November 2026

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