Math 2.0

Quantum theory Entanglement Example

Bell state

Builds on Tensor product of Hilbert spacesPartial trace

Example

Let ∣0⟩,∣1⟩|0\rangle, |1\rangle be the standard basis of ℂ2\C^2, and write ∣jk⟩=∣j⟩⊗∣k⟩|jk\rangle = |j\rangle \otimes |k\rangle in ℂ2⊗ℂ2\C^2 \otimes \C^2. The four Bell states are ∣Φ±⟩=∣00⟩±∣11⟩2,∣Ψ±⟩=∣01⟩±∣10⟩2.|\Phi^{\pm}\rangle = \frac{|00\rangle \pm |11\rangle}{\sqrt{2}}, \qquad |\Psi^{\pm}\rangle = \frac{|01\rangle \pm |10\rangle}{\sqrt{2}}. They are unit vectors and pairwise orthogonal, so they form an orthonormal basis of ℂ2⊗ℂ2\C^2 \otimes \C^2, the Bell basis. Each of them is entangled. For ∣Φ+⟩|\Phi^+\rangle, the coefficient matrix in the standard basis is 12I\tfrac{1}{\sqrt 2} I, which has rank 22, so it is not a product vector. The same holds for the other three, whose coefficient matrices are also invertible.

Remarks

The partial trace of ∣Φ+⟩⟨Φ+∣|\Phi^+\rangle\langle\Phi^+| over either factor is 12I\tfrac12 I. So each qubit alone is maximally mixed, while the pair is in a pure state: the Bell states are maximally entangled. The state ∣Ψ−⟩|\Psi^-\rangle is the singlet; it is the unique state, up to a phase, with (U⊗U)∣Ψ−⟩=det⁡(U) ∣Ψ−⟩(U \otimes U)|\Psi^-\rangle = \det(U)\,|\Psi^-\rangle for every unitary UU on ℂ2\C^2.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Bell_state
About this page
TagCA57HMCRQQ
URIm2://CA57HMCRQQ
Kindexample
WritingW0 stub
MSC81P40
Instance ofQuantum entanglement
UsesTensor product of Hilbert spaces, Partial trace
Same as
Changed3 November 2026

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